197.Rising Temperature
197.Rising Temperature
难度:Easy
给定一个 Weather 表,编写一个 SQL 查询,来查找与之前(昨天的)日期相比温度更高的所有日期的 Id。
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+---------+------------------+------------------+
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| Id(INT) | RecordDate(DATE) | Temperature(INT) |
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+---------+------------------+------------------+
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| 1 | 2015-01-01 | 10 |
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| 2 | 2015-01-02 | 25 |
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| 3 | 2015-01-03 | 20 |
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| 4 | 2015-01-04 | 30 |
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+---------+------------------+------------------+
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例如,根据上述给定的 Weather 表格,返回如下 Id:
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+----+
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| Id |
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+----+
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| 2 |
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| 4 |
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+----+
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需要認識DATEDIFF函數,主要是比較日期的,前者大返回1,後者大返回-1;
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Write your MySQL query statement below
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SELECT
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weather.id AS 'Id'
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FROM
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weather
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JOIN
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weather w ON DATEDIFF(weather.RecordDate, w.RecordDate) = 1
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AND weather.Temperature > w.Temperature
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;
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执行用时 :978 ms, 在所有 C++ 提交中击败了16.9%的用户 内存消耗 :N/A
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