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197.Rising Temperature
197.Rising Temperature
难度:Easy
给定一个 Weather 表，编写一个 SQL 查询，来查找与之前（昨天的）日期相比温度更高的所有日期的 Id。
+---------+------------------+------------------+
| Id(INT) | RecordDate(DATE) | Temperature(INT) |
+---------+------------------+------------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+---------+------------------+------------------+
例如，根据上述给定的 Weather 表格，返回如下 Id:
+----+
| Id |
+----+
| 2 |
| 4 |
+----+
需要認識
DATEDIFF函數，主要是比較日期的，前者大返回1，後者大返回-1； Write your MySQL query statement below
SELECT
weather.id AS 'Id'
FROM
weather
JOIN
weather w ON DATEDIFF(weather.RecordDate, w.RecordDate) = 1
AND weather.Temperature > w.Temperature
;
执行用时 :978 ms, 在所有 C++ 提交中击败了16.9%的用户 内存消耗 :N/A
Last modified 1yr ago