# 100.Same Tree

**100.Same Tree**

难度:Easy

> 给定两个二叉树，编写一个函数来检验它们是否相同。

如果两个树在结构上相同，并且节点具有相同的值，则认为它们是相同的。

```
示例 1:

输入:       1         1
          / \       / \
         2   3     2   3

        [1,2,3],   [1,2,3]

输出: true
示例 2:

输入:      1          1
          /           \
         2             2

        [1,2],     [1,null,2]

输出: false
示例 3:

输入:       1         1
          / \       / \
         2   1     1   2

        [1,2,1],   [1,1,2]

输出: false
```

简单题，直接递归。

```
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isSameTree(TreeNode* p, TreeNode* q) {
        if(p==NULL && q==NULL) return true;
        else if(p==NULL ||q == NULL) return false;
        return p->val == q->val && isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
    }
};
```

> 执行用时 : 8 ms, 在Same Tree的C++提交中击败了94.66% 的用户\
> 内存消耗 : 9.8 MB, 在Same Tree的C++提交中击败了76.94% 的用户


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