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633.Sum of Square Numbers
633.Sum of Square Numbers
难度:Easy
Given a non-negative integer c, your task is to decide whether there're two integers a and b such that a2 + b2 = c.
Example 1:
Input: 5
Output: True
Explanation: 1 * 1 + 2 * 2 = 5
Example 2:
Input: 3
Output: False
完全平方数，直接遍历一遍，判断差是否是完全平方。
class Solution {
bool isSquare(int n)
{
int tmp=sqrt(n);
return tmp*tmp == n;
}
public:
bool judgeSquareSum(int c) {
for(int i=0;i<=sqrt(c);i++)
{
if(isSquare(c-i*i) ) return true;
}
return false;
}
};
执行用时 :8 ms, 在所有 C++ 提交中击败了56.27%的用户 内存消耗 :8.1 MB, 在所有 C++ 提交中击败了76.25%的用户
Last modified 1yr ago