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# 476.Number Complement

**476.Number Complements**

难度:Easy

> 给定一个正整数，输出它的补数。补数是对该数的二进制表示取反。

注意: 给定的整数保证在32位带符号整数的范围内。 你可以假定二进制数不包含前导零位。

```
示例 1:

输入: 5
输出: 2
解释: 5的二进制表示为101（没有前导零位），其补数为010。所以你需要输出2。
示例 2:

输入: 1
输出: 0
解释: 1的二进制表示为1（没有前导零位），其补数为0。所以你需要输出0。
```

直接位运算，代码如下。

```
class Solution {
public:
    int findComplement(int num) {
        int t=num;
        int flag=0;
        int res=0;
        while(t)
        {
             res |= ((t&1^1)<<(flag++));
           // cout<<res<<endl;
            t=t>>1;
           // cout<<t<<endl;
            
        }
        return res;
    }
};
```


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