686.Repeated String Match - Leetcode题解

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9.Palindrome Number

13.Roman to Integer

19.Remove Nth Node from End of List

20.Valid Parentheses

21.Merge Two Sorted Lists

22.Generate Parentheses

26.Remove Duplicates from Sorted Array

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53.Maximum Subarray

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77.Combinations

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88.Merge Sorted Array

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119.Pascals Triangle II

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125.Valid Palindrome

131.Palindrome Partitioning

140.Word Break II

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204.Count Primes

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219.Contains Duplicate II

225.Implement Stack Using Queues

226.Invert Binary Tree

231.Power of Two

232.Implement Queue Using Stack

234.Palindrome Linked List

237.Delete Node in a Linked List

240.Search a 2D Matrix II

242.Valid Anagram

257.Binary Tree Paths

263.Ugly Numbers

268.Missing Number

278.First Bad Version

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345.Reverse Vowels of a String

349.Intersection of Two Arrays

350.Intersection of Two Arrays II

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371.Sum of Two Integers

374.Guess Number Higher or Lower

383.Ransom Note

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405.Convert A Number to Hexadecimal

409.Longest Palindrome

414.Third Maximum Number

415.Add Strings

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429.N Ary Tree Level Order Traversal

434.Number of Segments in a String

437.Path Sum III

438.Find All Anagrams in a String

441.Arranging Coins

443.String Compression

447.Number of Boomerangs

448.Find All Numbers Disappeared in an Array

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455.Assign Cookies

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461.Hamming Distance

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485.Max Consecutive Ones

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543.Diameter of Binary Tree

551.Student Attendace Record I

557.Reverse Words in a String

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561.Array Partition I

563.Binary Tree Tilt

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590.N Ary Tree Postorder Traversal

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686.Repeated String Match

687.Longest Univalue Path

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814.Binary Tree Pruning

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829.Consecutive Numbers Sum

830.Position of Large Groups

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833.Find And Replace in String

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859.Buddy Strings

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1395.Count Number of Teams

面试题 16.01

面试题 16.18

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686.Repeated String Match

686.Repeated String Match
难度:Easy
Given two strings A and B, find the minimum number of times A has to be repeated such that B is a substring of it. If no such solution, return -1.
For example, with A = "abcd" and B = "cdabcdab".
Return 3, because by repeating A three times (“abcdabcdabcd”), B is a substring of it; and B is not a substring of A repeated two times ("abcdabcd").
Note: The length of A and B will be between 1 and 10000.
可以将A循环补至长度大于B，然后判断B是否是增补的A的子集。 最后确定循环的A的次数。
class Solution {
public:
    int repeatedStringMatch(string A, string B) {
        int t= B.size()/A.size()+1;
        string tmp=A;
        while(t--)
        {
            tmp+=A;
        }
        size_t start= tmp.find(B);
        if(start ==string::npos) return -1;
        int end=start+B.size()-1;
        if(end == start) return 1;
     //      cout<<start<<" "<< end << endl;
        start = start/A.size() *A.size();
        end = ((end+1)/A.size()+((end+1)%A.size() !=0) ) *A.size();
       // cout<<start<<" "<< end << endl;
        return (end-start)/A.size();
            
    }
    };
执行用时 :12 ms, 在所有 C++ 提交中击败了97.00%的用户
内存消耗 :9.1 MB, 在所有 C++ 提交中击败了82.83%的用户

682.Baseball Game

687.Longest Univalue Path

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