> For the complete documentation index, see [llms.txt](https://dfine.gitbook.io/leetcode/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://dfine.gitbook.io/leetcode/506.relative_ranks.md).

# 506.Relative Ranks

**506.Relative Ranks**

难度:Easy

> 给出 N 名运动员的成绩，找出他们的相对名次并授予前三名对应的奖牌。前三名运动员将会被分别授予 “金牌”，“银牌” 和“ 铜牌”（"Gold Medal", "Silver Medal", "Bronze Medal"）。

(注：分数越高的选手，排名越靠前。)

示例 1:

```
输入: [5, 4, 3, 2, 1]
输出: ["Gold Medal", "Silver Medal", "Bronze Medal", "4", "5"]
解释: 前三名运动员的成绩为前三高的，因此将会分别被授予 “金牌”，“银牌”和“铜牌” ("Gold Medal", "Silver Medal" and "Bronze Medal").
余下的两名运动员，我们只需要通过他们的成绩计算将其相对名次即可。
```

提示:

N 是一个正整数并且不会超过 10000。 所有运动员的成绩都不相同。

可以通过排序得出索引，然后建立排名。

```
class Solution {
public:
    vector<string> findRelativeRanks(vector<int>& nums) {
        vector<string> res(nums.size(), "");
        vector<int> index;
        for(int i=0;i<nums.size();i++)
            index.push_back(i);
        sort(index.begin(), index.end(), [&nums](int a, int b){  return nums[a] > nums[b]; });
        if(nums.size()>=1) { res[index[0]]="Gold Medal";}
        if(nums.size()>=2) {res[index[1]]="Silver Medal";}
        if(nums.size()>=3) {res[index[2]]="Bronze Medal";}
        for(int i=3;i<nums.size();i++)
        {
         //   cout<<index[i]<<" "<<endl;
            res[index[i]]=to_string(i+1);
        }
        return res;
    }
};
```

> 执行用时 : 32 ms, 在Relative Ranks的C++提交中击败了82.09% 的用户\
> 内存消耗 : 11.2 MB, 在Relative Ranks的C++提交中击败了75.21% 的用户


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