> For the complete documentation index, see [llms.txt](https://dfine.gitbook.io/leetcode/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://dfine.gitbook.io/leetcode/557.reverse_words_in_a_string.md).

# 557.Reverse Words in a String

**557.Reverse Words in a String**

难度:Easy

> 给定一个字符串，你需要反转字符串中每个单词的字符顺序，同时仍保留空格和单词的初始顺序。

示例 1: 输入: "Let's take LeetCode contest" 输出: "s'teL ekat edoCteeL tsetnoc" 注意：在字符串中，每个单词由单个空格分隔，并且字符串中不会有任何额外的空格。

代码如下：

```
class Solution {
public:
    string reverseWords(string s) {
        vector<string> words;
        words.push_back(" ");
        for(auto w:s)
        {
            if(w==' ')
            {               
                words.push_back(" ");            
            }
            else
                words[words.size()-1]+=w;
           // cout<< words[words.size()-1]<<endl;
        }
        words[words.size()-1]=words[words.size()-1].substr(1,words[words.size()-1].length()-1);
      //  cout<< words[0]<<words[1]<<endl;
       // words[words.size()-1]+=' ';
        string res;
        for(auto w:words)
        {
            for(int i=w.length()-1;i>=0;i--)
            {
                res+=w[i];
         //       cout<<res;
            }
        }
        return res;
    }
};
```


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