# 905.Sort Array by Parity

**905.Sort Array by Parity**

难度:Easy

> 给定一个非负整数数组 A，返回一个由 A 的所有偶数元素组成的数组，后面跟 A 的所有奇数元素。 你可以返回满足此条件的任何数组作为答案。

```
示例：

输入：[3,1,2,4]
输出：[2,4,3,1]
输出 [4,2,3,1]，[2,4,1,3] 和 [4,2,1,3] 也会被接受。
 

提示：

1 <= A.length <= 5000
0 <= A[i] <= 5000
```

代码如下：

```
class Solution {
public:
    vector<int> sortArrayByParity(vector<int>& A) {
        vector<int> res;
        for(auto e: A)
           if(e%2==0) res.push_back(e);
        for(auto e: A)
            if(e%2) res.push_back(e);
        return res;
    }
};
```


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