> For the complete documentation index, see [llms.txt](https://dfine.gitbook.io/leetcode/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://dfine.gitbook.io/leetcode/66.plus_one.md).

# 66.Plus One

**66.Plus One**

难度:Easy

> 给定一个由整数组成的非空数组所表示的非负整数，在该数的基础上加一。 最高位数字存放在数组的首位， 数组中每个元素只存储一个数字。 你可以假设除了整数 0 之外，这个整数不会以零开头。

```
示例 1:

输入: [1,2,3]
输出: [1,2,4]
解释: 输入数组表示数字 123。
示例 2:

输入: [4,3,2,1]
输出: [4,3,2,2]
解释: 输入数组表示数字 4321。
```

代码如下：

```
class Solution {
public:
    vector<int> plusOne(vector<int>& digits) {
        int flag=1;
        int set=0;
        int len=digits.size();
        while(flag)
        {
            --len;
            if(digits[len]!=9)
            {
                digits[len]+=1;
                flag=0;
            }
            else 
            {
                digits[len]=0;
                if(len==0)
                {
                    set=1;
                    break;
                }
            }
        }
        cout<<set<<endl;
        if(set)
        {
            len=digits.size();
            vector<int>tmp(len+1,0);
            tmp[0]=1;
            for(int i=1;i<=len;i++)
                tmp[i]=digits[i-1];
            return tmp;
        }
        return digits;
    }
};
```


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